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PHP PHP Basics (Retired) PHP Data & Structure PHP Variables

Posted by Jairo Montenegro
Jairo Montenegro
3,687 Points

<?php $name = "Mike"; echo "$name"; ?> The online interpreter won't accept this. Help

What is going on?

index.php 
<?php 
$name = "Mike";
echo "$name";
?>

4 Answers

Tony Nguyen
Tony Nguyen
24,934 Points
Tony Nguyen
Tony Nguyen
24,934 Points

Hey Jairo,

Your putting in the string:

echo "$name";

This is not correct since your output will be a string instead of the variable that contains the value of the name "Mike". You will need to get rid of your quotes like so:

echo $name;
Jairo Montenegro
Jairo Montenegro
3,687 Points

Hey man thanks, I've tried that as well. What else could it be?

Tony Nguyen
Tony Nguyen
24,934 Points
Tony Nguyen
Tony Nguyen
24,934 Points

Make sure that your entire code looks like this:

<?php
$name = "Mike";
echo $name;
?>
Abe Layee
Abe Layee
8,378 Points
Abe Layee
Abe Layee
8,378 Points

By adding quotation mark around the the var name, it becomes a string.

<?php 
$name = "Mike";
echo "$name"; // this is a string
echo $name; //correct way
?>
jason chan
jason chan
31,009 Points
jason chan
jason chan
31,009 Points

you don't need quotes in variables you already defined it.

quotes are only for strings.

Logan Eppley
PLUS
Logan Eppley
Courses Plus Student 26,697 Points
Logan Eppley
Logan Eppley
Courses Plus Student 26,697 Points 
<?php
$name="Mike";
echo $name;
?>

If that does not work, I recommend that you refresh the browser and start the code challenge over again.