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CSS Sass Basics (retired) Variables, Mixins, and Extending Selectors Defining Variables

Luigi Rulloda
Luigi Rulloda
6,175 Points

Please help

I'm having a hard time figuring out the task 4 of 4 code challenge of Sass Variables.

index.html
<!DOCTYPE html>
<html>
<head>
  <title>Sass Basics - Code Challenge</title>
  <link rel="stylesheet" type="text/css" href="page-style.css">
  <link rel="stylesheet" type="text/css" href="style.css">
</head>
<body>
  <h1>Hampton's Blog</h1>
  <div class="sidebar">
    <div class="inner_sidebar">
      Thanks for the visit!
    </div>
  </div>
  <div class="entry">
    <h1>Delicious Food in SF</h1>
      <div class="content">
        <p>
          You know what my favorite restaurant in San Francisco is? The answer is that there are so many great restaurants that I couldn't choose one. But honorable mentions include <a href="#">Mr. Chow's</a>, <a href="#">Live Sushi</a> and <a href="#">Piccino</a>. 
          <a href="/info.html">Read More</a>
        </p>
    </div>
  </div>
</body>
</html>
style.scss
/* Write your SCSS code below. */
$lime: #090;
$sidebar_width: 100px;

a {
  color: $lime;
}

.inner_sidebar {
  width: $sidebar_width;
}

2 Answers

Jason Anders
MOD
Jason Anders
Treehouse Moderator 145,860 Points

Hey Luigi,

So far all your code is correct (Good Job). The final task (4/4) want you to set a rule that uses the variable, but is half the value... so, you just need to divide the variable by 2 inside of the rule.

.inner_sidebar {
  width: $sidebar_width / 2;
}

Hope that makes sense. Keep Coding! :dizzy:

Tobias Helmrich
Tobias Helmrich
31,603 Points

Hey,

the reason why you're not passing this task is that you have to set the width property of the element with the inner_sidebar class to the half of $sidebar_width. So if you divide the $sidebar_width variable by 2 it should work.

Like so:

/* Write your SCSS code below. */
$lime: #090;
$sidebar_width: 100px;

a {
  color: $lime;
}

.inner_sidebar {
  width: $sidebar_width / 2;
}

I hope that helps! :)