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Start your free trialLuigi Rulloda
6,175 PointsPlease help
I'm having a hard time figuring out the task 4 of 4 code challenge of Sass Variables.
<!DOCTYPE html>
<html>
<head>
<title>Sass Basics - Code Challenge</title>
<link rel="stylesheet" type="text/css" href="page-style.css">
<link rel="stylesheet" type="text/css" href="style.css">
</head>
<body>
<h1>Hampton's Blog</h1>
<div class="sidebar">
<div class="inner_sidebar">
Thanks for the visit!
</div>
</div>
<div class="entry">
<h1>Delicious Food in SF</h1>
<div class="content">
<p>
You know what my favorite restaurant in San Francisco is? The answer is that there are so many great restaurants that I couldn't choose one. But honorable mentions include <a href="#">Mr. Chow's</a>, <a href="#">Live Sushi</a> and <a href="#">Piccino</a>.
<a href="/info.html">Read More</a>
</p>
</div>
</div>
</body>
</html>
/* Write your SCSS code below. */
$lime: #090;
$sidebar_width: 100px;
a {
color: $lime;
}
.inner_sidebar {
width: $sidebar_width;
}
2 Answers
Jason Anders
Treehouse Moderator 145,860 PointsHey Luigi,
So far all your code is correct (Good Job). The final task (4/4) want you to set a rule that uses the variable, but is half the value... so, you just need to divide the variable by 2 inside of the rule.
.inner_sidebar {
width: $sidebar_width / 2;
}
Hope that makes sense. Keep Coding!
Tobias Helmrich
31,603 PointsHey,
the reason why you're not passing this task is that you have to set the width property of the element with the inner_sidebar class to the half of $sidebar_width. So if you divide the $sidebar_width variable by 2 it should work.
Like so:
/* Write your SCSS code below. */
$lime: #090;
$sidebar_width: 100px;
a {
color: $lime;
}
.inner_sidebar {
width: $sidebar_width / 2;
}
I hope that helps! :)