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Python Python Basics (2015) Shopping List App Continue

Mo B
PLUS
Mo B
Courses Plus Student 493 Points

Please help

Hi, I'm having trouble with this one. Please help. Thank you.

breaks.py
def loopy(items):
    # Code goes here
    for member in items:
        if member.index[0] == "a":
            continue
        else:
            print(items)

1 Answer

Idan Melamed
Idan Melamed
16,285 Points

Hi Mo.

Every item in the items list is a string. So when they are asking if the 0 index of the item is 'a', they are actually trying to see if the first character of the string is 'a'.

To do that we can write the following code:

def loopy(items):
    # Code goes here
    for item in items:
        if item[0] == 'a':
            continue
        print(item)