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Start your free trialLuca Di Pinto
8,051 PointsPossible with this code?
Hi guys, I don't understand the logic of the "do.. while loop". I mean.. Could it be possible to use this code?
do { guess = prompt('I am thinking of a number between 1 and 10. What is it?'); guessCount +=1; }
while ( ! parseInt(guess)===randomNumber)
Thanks for the answers! Luca
3 Answers
jcorum
71,830 PointsHas a few bugs. Try this:
var secretNumber = Math.floor(Math.random() * 10 + 1);
var guessCount = 0;
do {
guess = prompt('I am thinking of a number between 1 and 10. What is it?');
guessCount +=1;
} while ( parseInt(guess) !== secretNumber);
alert("You guessed the secret number " + secretNumber + " in " + guessCount + " tries.");
First, get a random number between 1 and 10. Not sure what your randomnumber is, but it's undeclared and un-initialized.
Second, declare a variable to use to count up the user's guesses.
Third, modify the condition of the loop so that it runs until the user enters the secret number.
Note that there's a difference between !parseInt(guess) === secretNumber and parseInt(guess) !== secretNumber The former tries to apply the unary ! operator to an int, which won't fly. The latter says the guess isn't equal to the secret number.
Finally, you use a guessCount variable, but you don't initialize it or use it. So I put it to use in the last line of code.
Luca Di Pinto
8,051 PointsUhm... I lost something!!! Where do you declare the variable secretNumber?
So it's possible to use this code instead of the one shown in the video? The result is the same?
jcorum
71,830 PointssecretNumber is declared in this line:
var secretNumber = Math.floor(Math.random() * 10 + 1);
Re the video. Yes, it works the same.
john larson
16,594 Pointsjohn larson
16,594 Pointsj, as always apothegmatic.