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Start your free trialJames Williamson
1,486 Pointspreview of code works but exercise fails
When I run the preview of the code the results are correct. I can change the condition and still get the result I would expect but the exercise fails with
You need to check that $studentOneGPA = 4.0
Can you advise what I'm doing wrong
<?php
$studentOneName = 'Dave';
$studentOneGPA = 3.8;
$studentTwoName = 'Treasure';
$studentTwoGPA = 4.0;
//Place your code below this comment
If ($studentOneGPA == 4.0 ) { echo $studentOneName . " made the Honor Roll" ; }
else { echo $studentOneName . " has a GPA of ",$studentOneGPA . " " ;}
If ($studentTwoGPA == 4.0 ) { echo $studentTwoName . " made the Honor Roll" ; }
else { echo $studentTwoName . " has a GPA of " . $studentTwoGPA ;}
?>
1 Answer
Steven Parker
231,184 PointsYou're really close! But since the language is case-sensitive, "If" (with a capital "I") is not the same thing as "if" (with lower-case "i"). Just remove the capitalization from those keywords and you'll pass.
James Williamson
1,486 PointsJames Williamson
1,486 PointsThank you Steven. Much appreciated Regards Jim
Steven Parker
231,184 PointsSteven Parker
231,184 PointsJames Williamson — Glad to help. You can mark a question solved by choosing a "best answer".
And happy coding!