Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

PHP PHP Basics Daily Exercise Program Conditionals

preview of code works but exercise fails

When I run the preview of the code the results are correct. I can change the condition and still get the result I would expect but the exercise fails with

You need to check that $studentOneGPA = 4.0

Can you advise what I'm doing wrong

index.php
<?php
$studentOneName = 'Dave';
$studentOneGPA = 3.8;

$studentTwoName = 'Treasure';
$studentTwoGPA = 4.0;

//Place your code below this comment
If ($studentOneGPA == 4.0 ) { echo $studentOneName . " made the Honor Roll" ;  }
   else { echo $studentOneName . " has a GPA of ",$studentOneGPA . " " ;}

If ($studentTwoGPA == 4.0 ) { echo $studentTwoName . " made the Honor Roll" ; }
   else { echo $studentTwoName . " has a GPA of " .  $studentTwoGPA ;}
?>

1 Answer

Steven Parker
Steven Parker
231,184 Points

You're really close! But since the language is case-sensitive, "If" (with a capital "I") is not the same thing as "if" (with lower-case "i"). Just remove the capitalization from those keywords and you'll pass.

Thank you Steven. Much appreciated Regards Jim

Steven Parker
Steven Parker
231,184 Points

James Williamson — Glad to help. You can mark a question solved by choosing a "best answer".
And happy coding!