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PHP Integrating PHP with Databases Using Relational Tables Understanding SQL Injections

Qasim Hafeez
Qasim Hafeez
12,731 Points
Posted by Qasim Hafeez
Qasim Hafeez
12,731 Points

Question about media_id

When I added "media_id" to the query like she does in the video, I got an error saying the 'media_id' was ambiguous. I changed it to "Media.media_id" and it worked. I thought I would have to add "Media.media_id" to the get_item_html function but that threw an error also. When I changed it back to "media_id" it worked. Does anyone know why this is?

1 Answer

Dennis Amiel Domingo
Dennis Amiel Domingo
15,357 Points
Dennis Amiel Domingo
Dennis Amiel Domingo
15,357 Points

You might have added the "media_id" column in the "single_item_array" function. It should be added in the "full_catalog_array" function in the function.php file.

Add here:

function full_catalog_array(){
    include("connection.php");
    try {
    $results = $db->query("SELECT media_id, title, category, img FROM media");
    //echo "Retrieved Results";
    } catch (Exception $e) {
        echo "Unable to retrieve results";
        exit;
    }
    $catalog = $results->fetchAll(PDO::FETCH_ASSOC);
    return $catalog;
}

Note here:

function single_item_array($id){
    include("connection.php");
    try {
    $results = $db->query(
        "SELECT title, category, img, format, year, genre, publisher, isbn
        FROM media
        JOIN genres ON media.genre_id = genres.genre_id
        LEFT OUTER JOIN books ON media.media_id = books.media_id
        WHERE media.media_id = $id"
    );
    } catch (Exception $e) {
        echo "Unable to retrieve results\n";
        echo $e;
        exit;
    }
    $catalog = $results->fetch(PDO::FETCH_ASSOC);
    return $catalog;
}

Note: Sorry if my query is a little different than the one in the videos. I created my own database at home that's slightly different from this one.