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Anthony Sims Jr.
Courses Plus Student 2,413 Pointsrequest.open('GET', 'footer.html') not working?
I've watched video twice and checked AJAX formatting on w3schools course. Just don't know what I'm doing wrong.
var request = new XMLHttpRequest();
request.onreadystatechange = function () {
if (request.readyState === 4) {
document.getElementById("footer").innerHTML = request.responseText;
};
request.open("GET", "footer.html");
request.send();
};
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>AJAX with JavaScript</title>
<script src="app.js"></script>
</head>
<body>
<div id="main">
<h1>AJAX!</h1>
</div>
<div id="footer"></div>
</body>
</html>
Anthony Sims Jr.
Courses Plus Student 2,413 PointsTHANK YOU, REGENA!
I ignored the if statement because it was prepopulated in the lesson. Now I know better.
Thanks again!
Regena Koeshall
Front End Web Development Techdegree Graduate 21,143 PointsRegena Koeshall
Front End Web Development Techdegree Graduate 21,143 PointsYou are missing a closing curly bracket at the end of if statement. Should be
var request = new XMLHttpRequest(); request.onreadystatechange = function () { if (request.readyState === 4) { document.getElementById("footer").innerHTML = request.responseText; } }; request.open("GET", "footer.html"); request.send(); };