Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Java Java Objects (Retired) Delivering the MVP Validation

Marcus Schumacher
Marcus Schumacher
16,616 Points

Shouldn't this work?

Prompt:

I've added the method validatedFieldName it will return the validated field name. If the value passed in doesn't meet the requirements, throw an IllegalArgumentException. I'll keep you posted on the results every time you press check work.

I don't understand why this isn't working.

TeacherAssistant.java
public class TeacherAssistant {

  public static String validatedFieldName(String fieldName) {
    // These things should be verified:
    // 1.  Member fields must start with an 'm'
    if(fieldName.indexOf(0) != "m") {
      throw IllegalArgumentException("Field name does not start with an m"); 
    }
    // 2.  The second letter in the field name must be uppercased to ensure camel-casing
    if(fieldName.indexOf(0) != fieldName.indexOf(0).toUpperCase()) {
      throw IllegalArgumentException("Your second letter must be an uppercase letter");
    }


    // NOTE:  To check if something is not equal use the != symbol. eg: 3 != 4
    return fieldName;
  }

}

2 Answers

Ruud Claassen
Ruud Claassen
9,359 Points

Hi Markus, make sure you use the correct method to retrieve a character at a given position in a string.

.indexOf() returns the index number of a given character. In this case, using charAt() would be the way to go to retrieve a character at a given index number.

When throwing an exception, make sure to also include the 'new' keyword.

Java has some existing methods to check whether a character is uppercase or lowercase, for example with character 'c':

  • Character.isUpperCase('c') (will return false)
  • Character.isLowerCase('c') (will return true)

Perhaps you can now tweak your code so it works?

Marcus Schumacher
Marcus Schumacher
16,616 Points

I revised my code :( still doesn't work

public class TeacherAssistant {

public static String validatedFieldName(String fieldName) { public static String validatedFieldName(String fieldName) { // These things should be verified: // 1. Member fields must start with an 'm' if(fieldName.indexOf(0) != "m") { throw IllegalArgumentException("Field name does not start with an m"); } // 2. The second letter in the field name must be uppercased to ensure camel-casing

  boolean isUpperCase = Character.isUpperCase(fieldName.charAt(1));

if(!isUpperCase) {
  throw new IllegalArgumentException("Your second letter must be an uppercase letter");
}
return fieldName;

}

}

Ruud Claassen
Ruud Claassen
9,359 Points
  • Make sure to use the .charAt() method
  • Make sure to use the 'm' character instead of the "m" String

Your code for checking the uppercase should be fine.

public class TeacherAssistant {

  public static String validatedFieldName(String fieldName) {
    // These things should be verified:
    // 1.  Member fields must start with an 'm'

    if( fieldName.charAt(0) != 'm' ){
      throw new IllegalArgumentException("Field name does not start with an m"); 
    }

    // 2.  The second letter in the field name must be uppercased to ensure camel-casing

  boolean isUpperCase = Character.isUpperCase(fieldName.charAt(1));

  if(!isUpperCase) {
     throw new IllegalArgumentException("Your second letter must be an uppercase letter");
 }

    return fieldName;
  }
}
Marcus Schumacher
Marcus Schumacher
16,616 Points

Thanks that worked. I appreciate your help :)