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iOS Swift 2.0 Protocols Creating Flexible Objects Using Protocols Protocol Inheritance

3 Answers

Oliver Duncan
Oliver Duncan
16,642 Points

I don't think the compiler likes the space between 'PetType' and your colon. Format it like this, and it'll work:

protocol AnimalType {
    var numberOfLegs: Int { get }

protocol PetType: AnimalType {
    var cuddlyName: String { get }