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Eric Palumbo
6,313 PointsSimple PHP Application Stage 4 More excitement with Arrays challenge 6/7
QUESTION Inside the foreach loop, we should only display one <li> tag for each flavor. The one list item should display the value for the array element that the foreach loop is considering. Remove one of the <li> elements, and change the value that gets displayed in the other to display the flavor.
MY ANSWER <?php
$flavors = array("Chocolate","Vanilla", "Strawberry")
?> <p>Welcome to Ye Olde Ice Cream Shoppe. We sell <?php echo count($flavors); ?> flavors of ice cream.</p> <ul> <?php foreach ($flavors as $flavor) { ?> <li> echo $flavor</li> <? } ?> </ul>
I have tried a million different things please help
2 Answers
Coco Jackowski
12,914 PointsI haven't done this challenge, but the question does mention displaying list item (<li>) tags. Your code simply echos out the flavor values, not inside any HTML tags. Maybe if you echo out the values inside of <li> tags it will be correct?
Eric Palumbo
6,313 Pointsi had it in the <li> tags didnt work, but i didnt but HTML tags but it wasnt a problem for the last 5 before it