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iOS

Posted by Di Lisa Giuseppe
Di Lisa Giuseppe
2,129 Points

Solution for : Function and Optionals : Is Divisible

This is my solution for , i like to know if this is a good solution:)

            <p>This is code!</p>
            ```        

(func isDivisble(operand1:Int,operand2:Int) -> (IsDiv:Bool?,Result:String?)

    if operand1 / operand2 == 0  {

        return (nil,"Not Divisble")

    }


        return (true,"Divisble")




let result = isDivisble(10, 2)
if result.IsDiv == true{
println("number is \(result.Result!), result:\(result.IsDiv!)")
}
else{
println("Number is not Divisble")
}
}

1 Answer

Di Lisa Giuseppe
Di Lisa Giuseppe
2,129 Points
Di Lisa Giuseppe
Di Lisa Giuseppe
2,129 Points

!!