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Leonardo Diaz
17,591 Pointsthe Session's method createCriteria is deprecated, how should I proceed for establishing Class criteria?
/It says I should use JPA criteria, not sure how to use it :(/
@Deprecated Criteria createCriteria(Class persistentClass);
/**
* Create {@link Criteria} instance for the given class (entity or subclasses/implementors), using a specific
* alias.
*
* @param persistentClass The class, which is an entity, or has entity subclasses/implementors
* @param alias The alias to use
*
* @return The criteria instance for manipulation and execution
*
* @deprecated (since 5.2) for Session, use the JPA Criteria
*/
3 Answers

Leonardo Diaz
17,591 PointsThank you very much, I already came up with an answer here at https://docs.jboss.org/hibernate/entitymanager/3.5/reference/en/html/querycriteria.html
Ended up this way
private static List<Contact> fetchAllContacts(){
//Open Session
Session session = sessionFactory.openSession();
/* //Deprecated Way
* Criteria criteria = session.createCriteria(Contact.class);
* List<Contacts> contacts = criteria.list(); */
//Get Criteria Builder
CriteriaBuilder builder = session.getCriteriaBuilder();
//Create Criteria
CriteriaQuery<Contact> criteria = builder.createQuery(Contact.class);
Root<Contact> contactRoot = criteria.from(Contact.class);
criteria.select(contactRoot);
//Use criteria to query with session to fetch all contacts
List<Contact> contacts = session.createQuery(criteria).getResultList();
//Close session
session.close();
return contacts;
}

hbdc
13,725 PointsI had asked about this a few weeks back.
Chris Ramacciotti
Has suggested a solution for 'Spring with Hibernate' here:
https://github.com/treehouse/giflib-hibernate/commit/f97a2828a466e849d8ae84884b5dce60a66cf412
Take a look.
If you are watching 'Hibernate Basics' that will also work.

Leonardo Diaz
17,591 PointsLOL!
it was explained in the teacher's notes... I just saw it XD!
hbdc
13,725 Pointshbdc
13,725 PointsCool : )