Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trial
William Mordan
2,756 PointsThis code works in xcode playground but does not pass the challenge test. What is wrong?
For this challenge, we'd like to know in a range of values from 1 to 100, how many numbers are both odd, and a multiple of 7.
To start us off, I've written a for loop to iterate over the desired range of values and named the local constant n. Your job is to write an if statement inside the for loop to carry out the desired checks.
If the number is indeed both an odd number and a multiple of 7, append the value to the results array provided.
Hint: To check for an odd number you can either use the remainder operator and 3, or use the not operator to check for "not even"
var results: [Int] = []
for n in 1...100 { // Enter your code below if n % 7 == 0 && n % 2 == 1 { results.append(1) } else { results.append(0) } // End code }
var cnt = results.reduce(0) {$0 + $1}
print( "The array: = (results)") print( "The number of numbers between 1 and 100 that are both odd and divisible by 7: = (cnt)")
THE OUTPUT……….
The array: = [0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0] The number of numbers between 1 and 100 that are both odd and divisible by 7: = 7
1 Answer
ianhan3
4,263 PointsYou overthought the question I think. It just wants you to use your initial if statement and append the results array with the actual numbers that are both odd and divisible by 7. Else do nothing is suitable for the challenge.
for n in 1...100 {
if n % 7 == 0 && n % 2 == 1 {
results.append(n) }
else {
}
}
ianhan3
4,263 Pointsianhan3
4,263 PointsI walk through it in more depth here: https://teamtreehouse.com/community/i-need-help-no-not-get-it
William Mordan
2,756 PointsWilliam Mordan
2,756 PointsThanks Ian. I've got it now!