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General Discussion

This code works in xcode playground but does not pass the challenge test. What is wrong?

For this challenge, we'd like to know in a range of values from 1 to 100, how many numbers are both odd, and a multiple of 7.

To start us off, I've written a for loop to iterate over the desired range of values and named the local constant n. Your job is to write an if statement inside the for loop to carry out the desired checks.

If the number is indeed both an odd number and a multiple of 7, append the value to the results array provided.

Hint: To check for an odd number you can either use the remainder operator and 3, or use the not operator to check for "not even"

var results: [Int] = []

for n in 1...100 { // Enter your code below if n % 7 == 0 && n % 2 == 1 { results.append(1) } else { results.append(0) } // End code }

var cnt = results.reduce(0) {$0 + $1}

print( "The array: = (results)") print( "The number of numbers between 1 and 100 that are both odd and divisible by 7: = (cnt)")

THE OUTPUT……….

The array: = [0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0] The number of numbers between 1 and 100 that are both odd and divisible by 7: = 7

1 Answer

You overthought the question I think. It just wants you to use your initial if statement and append the results array with the actual numbers that are both odd and divisible by 7. Else do nothing is suitable for the challenge.

for n in 1...100 {  
if n % 7 == 0 && n % 2 == 1 { 
results.append(n) } 
else { 
}
}

Thanks Ian. I've got it now!