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iOS Build a Playlist Browser with Swift Building the Music Library and Playlist Models Struct Initialization

Posted by Aman Kansal
Aman Kansal
2,966 Points

title = playlistDictionary["title"] as String! I am getting '(String, NSObject) is not convertible to String' error?

i have tried changing the code to

title = playlistDictionary["title"]! as? String

it was something i found on the internet but this also doesn't seem to work. please help!

4 Answers

Chris Shaw
Chris Shaw
26,676 Points
Chris Shaw
Chris Shaw
26,676 Points

Hi Aman,

Try the following instead as you're attempting to unwrap the dictionary value then down cast it which won't work in this case.

title = playlistDictionary["title"] as String

Hope that helps.

Alx Ki
seal-mask
.a{fill-rule:evenodd;}techdegree seal-36
Alx Ki
Python Web Development Techdegree Graduate 14,822 Points
Alx Ki
.a{fill-rule:evenodd;}techdegree seal-36
Alx Ki
Python Web Development Techdegree Graduate 14,822 Points

Hi, Chris,

Maybe you have another solution? I even installed old xcode 6.0.1, but still have that error. (String, NSObject) is not convertible to String.

Aman Kansal
Aman Kansal
2,966 Points
Aman Kansal
Aman Kansal
2,966 Points

Hey Chris,

The original code I tried was:

title = playlistDictionary["title"] as String!

I also tried your code above and got the same error: '(String, NSObject)' is not convertible to 'String'

Would you have any other idea what could be happening?

HO WANG CHENG
HO WANG CHENG
8,694 Points
HO WANG CHENG
HO WANG CHENG
8,694 Points

Hi Aman

try

title = playlistDictionary["title"] as NSString

Rasmus Rønholt
PLUS
Rasmus Rønholt
Courses Plus Student 17,358 Points
Rasmus Rønholt
Rasmus Rønholt
Courses Plus Student 17,358 Points

I know this was asked a while ago... Anyways, I don't know if there is a Swift version discrepancy, but I don't understand why the speaker is unwrapping the result, when he is assigning it to an optional anyway - title:String? still needs to be unwrapped when accessed later. The following should work...

title = playlistDictionary["title"] as? String
Rasmus Rønholt
Rasmus Rønholt
Courses Plus Student 17,358 Points

Nb. Note the ? trailing 'as' which is the only difference to Chris' suggestion :)