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JavaScript AJAX Basics Programming AJAX Programming AJAX Solution

Posted by Amy Tomey
Amy Tomey
12,847 Points

Uncaught SyntaxError: Unexpected token '{' widget.js:24 line 24: if(roomRequest.readyState === 4 {

I cannot find the error in here... Thanks in advance for the review.

var roomRequest = new XMLHttpRequest();
roomRequest.onreadystatechange = function () {
  if(roomRequest.readyState === 4 {
    var rooms = JSON.parse(roomRequest.responseText);
    var statusHTML = '<ul class="rooms">';
    for (var i=0; i<rooms.length; i += 1) {
      if (rooms[i].available === true) {
        statusHTML += '<li class="empty">';
      } else {
        statusHTML += '<li class="full">';
      }
      statusHTML += roooms[i].room;
      statusHTML += '</li>';
    }
    statusHTML += '</ul>';
    document.getElementById('roomList').innerHTML = statusHTML;
  }
};
roomRequest.open('GET', '../data/rooms.json');
roomRequest.send();

var roomRequest = new XMLHttpRequest();
roomRequest.onreadystatechange = function () {
  if(roomRequest.readyState === 4 {
    var rooms = JSON.parse(roomRequest.responseText);
    var statusHTML = '<ul class="rooms">';
    for (var i=0; i<rooms.length; i += 1) {
      if (rooms[i].available === true) {
        statusHTML += '<li class="empty">';
      } else {
        statusHTML += '<li class="full">';
      }
      statusHTML += roooms[i].room;
      statusHTML += '</li>';
    }
    statusHTML += '</ul>';
    document.getElementById('roomList').innerHTML = statusHTML;
  }
};
roomRequest.open('GET', '../data/rooms.json');
roomRequest.send();

2 Answers

Sascha Bratton
Sascha Bratton
3,671 Points
Sascha Bratton
Sascha Bratton
3,671 Points

You are missing the closing paren on your conditional. Should be: if (roomRequest.readyState === 4) {

Sardar Ahmed Khan
Sardar Ahmed Khan
308 Points
Sardar Ahmed Khan
Sardar Ahmed Khan
308 Points

Replace the line with following line, it hopefully solves your error!

if(roomRequest.readyState === 4){