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Aymane Elaa
Python Web Development Techdegree Student 206 Pointsuse remove in for loops
lately i was searching some exercices about lists to practise and i found this exercise: Take two lists, say for example these two:
a = [1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89]
b = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13]
and write a program that returns a list that contains only the elements that are common between the lists (without duplicates). Make sure your program works on two lists of different sizes.>> so I tried this way : a= [1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89]; b = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13]; c=a; for element in a:; if element not in b :; c.remove(element); print(c) ; but it didn't give me the right answer it gives me this : [1, 1, 2, 3, 5, 8, 13, 34, 89]; can someone help me to understand please ??
1 Answer
Grigorij Schleifer
10,365 PointsHi Aymane, you can use the intersection method of a set object.
a = [1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89]
b = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13]
# to access the intersection method
# you have to convert "a" to a set
common = set(a).intersection(b)
print(common)
The intersection method will return a SET of numbers that both elements have in common. If you need to return a list, you can convert a set to a list using a list() method. I am not shure how efficient this code is (I am a python beginner myself). Let me know what you think ...