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PHP

Posted by CRYSTAL MORRIS
CRYSTAL MORRIS
Courses Plus Student 2,809 Points

What Is This Question Asking???

Challenge task 4 of 4 Change the value in the flavor variable to cookie dough. Preview the code and make sure the message appears.

(I Have Answered This Cookie Dough Question Every Way That I Could Imagine, Here re My Answers Foe Questions 1 thru 3 )

<?php
if ($flavor  = "vanilla")
echo "<p>Your favorite flavor of ice cream is ";
echo "vanilla";
echo ".</p>";
if ($flavor == "vanilla"){ echo "on"; } "<p>Randy's favorite flavor is cookie dough, also!</p>";
".</p>"; 

?>

1 Answer

Robert Walker
Robert Walker
17,146 Points
Robert Walker
Robert Walker
17,146 Points

Hi Crystal,

What you are missing is that you must change the "Value" in the "Variable".

<?php

$variable = "change this to cookie dough";

?>

So the value above is: "change this to cookie dough"

<?php
if ($flavor  = "cookie dough")
echo "<p>Your favorite flavor of ice cream is ";
echo "cookie dough";
echo ".</p>";
if ($flavor == "cookie dough"){ echo "on"; } "<p>Randy's favorite flavor is cookie dough, also!</p>";
".</p>"; 

?>