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Python Python Collections (Retired) Tuples Combo

Posted by Fox guy
Fox guy
1,802 Points

Why are the results different?

I know that the code is wrong but why am I getting different results in the challenge than workspaces. At the same time I am really confused, could use help on breaking down the problem.

zippy.py 
# combo(['swallow', 'snake', 'parrot'], 'abc')
# Output:
# [('swallow', 'a'), ('snake', 'b'), ('parrot', 'c')]
# If you use list.append(), you'll want to pass it a tuple of new values.
# Using enumerate() here can save you a variable or two.

def combo(value_set, label):
  result = []
  count = 0
  for label, item in enumerate(value_set):
    result.append('{}, {}'.format(item, count))
    count += 1
    tuple(result)
  return (tuple(result))


print(combo(['T','r','e','e','h','o','u','s','e'], 'abc'))

1 Answer

Dan Johnson
Dan Johnson
40,532 Points
Dan Johnson
Dan Johnson
40,532 Points

When you're using enumerate you're only pulling the values from one of the iterables. With:

for label, item in enumerate(value_set):

label will become the index/count generated by enumerate, and item will be the value in value_set. So the challenge is probably passing in a list of numbers which will cause you to get a list with tuples only containing numbers.

What you can use enumerate for is to generate an index for the other iterable (left and right being the iterables):

  for index, left_val in enumerate(left):
    combo.append( (left_val, right[index]) )