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Bryan Woodard
5,757 PointsWhy does this work and not the other?
Why does this code return undefined when dice10.roll() is called?
function dice(sides){
this.sides = sides;
this.roll = function (){
console.log( Math.floor(Math.random() * this.sides) + 1);
};
}
var dice10 = new dice(10);
dice10.roll();
but this one actually works
function dice(sides){
this.sides = sides;
this.roll = function (){
return Math.floor(Math.random() * this.sides) + 1;
};
}
var dice10 = new dice(10);
dice10.roll();
1 Answer
Paul Cox
12,671 PointsThe accepted answer is incorrect. The first example doesn't return the roll value in the roll function, it logs it to the console. A function returns undefined if a value was not returned. Therefore, when running the code in the console, the 1st example will display the roll value then undefined in the console, whereas the 2nd example will only display the roll value.