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JavaScript JavaScript Loops Working with 'for' Loops The Refactor Challenge – Duplicate Code

Posted by Ahmad Hill
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Ahmad Hill
Full Stack JavaScript Techdegree Student 1,883 Points

why does using an arrow function work but not a function declaration?

I tried to use a function declaration in place of the arrow function and the program didn't run. why doesn't it work?

Ahmad Hill
.a{fill-rule:evenodd;}techdegree
Ahmad Hill
Full Stack JavaScript Techdegree Student 1,883 Points

can you use this Alexander Besse?

https://w.trhou.se/fasau82nzq

2 Answers

Peter Vann
Peter Vann
36,425 Points
Peter Vann
Peter Vann
36,425 Points

Hi Ahmad!

If I understand your question properly, I think the issue comes down to arrow function shorthand syntax as explained here:

https://teamtreehouse.com/library/javascript-functions/arrow-functions/concise-arrow-function-syntax#arrow-functions-as-one-line-statements

To work, this:

const square = num => (num * num) ;

Would need to be converted to this (as a regular function declaration):

const square = function(num) { return (num * num) };

(the return being the key factor in the second code block)

I hope that helps.

Stay safe and happy coding!

Ahmad Hill
.a{fill-rule:evenodd;}techdegree
Ahmad Hill
Full Stack JavaScript Techdegree Student 1,883 Points

I understand the syntax of an arrow function. my question is pertaining to something else but thanks for the help though.

Courtney Wilson
Courtney Wilson
8,031 Points
Courtney Wilson
Courtney Wilson
8,031 Points

Your function getColor() isn't returning anything:

function getColor() {
  Math.floor(Math.random() * 256);
}

Add a return statement to return the random color value for it to work:

function getColor() {
  return Math.floor(Math.random() * 256);
}