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General Discussion

Rob Szopinski
Rob Szopinski
9,818 Points
Posted by Rob Szopinski
Rob Szopinski
9,818 Points

Why is code only working when chaining methods?

I am following along with Treasure and double-checking, triple-checking that my code is the same. I will create the const variable and then call the variable later on and I am not getting the intended action. However, when I chain the methods, then my code starts working.

For example: This doesn't work:

const $secureLinks = $('a[href^="https://"]')

$secureLinks.addClass('secure');

This works:

const $secureLinks = $('a[href^="https://"]').addClass('secure');

Is this okay? Am I going to run into problems later with hard-coding or the like? Is there a setting on my browser that I need to look into. I had issues with using the download attribute earlier and saw that need to change privacy settings.

Thanks in advance!

1 Answer

KRIS NIKOLAISEN
KRIS NIKOLAISEN
54,967 Points
KRIS NIKOLAISEN
KRIS NIKOLAISEN
54,967 Points

I pasted your code:

const $secureLinks = $('a[href^="https://"]')
$secureLinks.addClass('secure');

into app.js for this video's workspace. And I can see the links styled with the css. In inspecting the elements with developer's tools I can see the class was added. So I'm not sure what you are seeing.