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JavaScript

Posted by Thanitsak Leuangsupornpong
Thanitsak Leuangsupornpong
7,490 Points

why my code doesn't stop in the while loop(in do while)when I write done,it will go,and go

Here my code

do{ guess=prompt("I am thinking the number of 1 to 10,What is its?"); Count=guessCount+1;

if(guess.toLowerCase()=="done"){
    checkG=true;
}else if(guess==randomNumber){
    checkG=true;
}else if(guess!=randomNumber){
    var G;

    while(G!=randomNumber){
        G=prompt(getRandomWord(10));
        Count=Count+1;
        if(G=="done"){checkG=true;}else if(G==randomNumber){checkG=true;}
        }
    }

}

while(!checkG)

3 Answers

Sara Chicazul
Sara Chicazul
7,475 Points

In the inner loop your exit condition is while(G!=randomNumber). No matter what else you do, so long as G is not equal to randomNumber, you will be stuck inside the inner loop and never get to the end of your do...while loop! The code never gets as far as the line while(!checkG) unless you break out of the inner loop first.

Thanitsak Leuangsupornpong
Thanitsak Leuangsupornpong
7,490 Points
Thanitsak Leuangsupornpong
Thanitsak Leuangsupornpong
7,490 Points

thank you very much Sara how to break out the inner loop?

Sara Chicazul
Sara Chicazul
7,475 Points

To be honest I don't understand why you need the second loop at all! Most of the code seems to be the same, so why can't you just use one loop?

If you don't want to change the code that much: try changing the while statement to say while(G!=randomNumber && !checkG)

Thanitsak Leuangsupornpong
Thanitsak Leuangsupornpong
7,490 Points
Thanitsak Leuangsupornpong
Thanitsak Leuangsupornpong
7,490 Points

Thank you very much now it work!