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Ryan Moody
20,498 PointsWhy Wont this code work? if (request.re
var request = new XMLHttpRequest(); request.onreadystatechange = function () { if (request.readyState === 4) {
document.getElementById("footer").innerHTML = request.responseText;
}
request.open("GET", "footer.html",true);
};
var request = new XMLHttpRequest();
request.onreadystatechange = function () {
if (request.readyState === 4) {
document.getElementById("footer").innerHTML = request.responseText;
}
request.open("GET", "footer.html",true);
};
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>AJAX with JavaScript</title>
<script src="app.js"></script>
</head>
<body>
<div id="main">
<h1>AJAX!</h1>
</div>
<div id="footer"></div>
</body>
</html>
2 Answers
Simon Coates
28,694 Pointsit looks like you're calling the request inside the response function. so maybe:
var request = new XMLHttpRequest();
request.onreadystatechange = function () {
if (request.readyState === 4) {
document.getElementById("footer").innerHTML = request.responseText;
}
};
request.open("GET", "footer.html", true);
Ryan Moody
20,498 PointsIt worked! Thank you so much!