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Peter Falcone
Courses Plus Student 1,108 Pointsa little confusion with even.py
this is my best shot, haven't submitted it yet, because for one thing, I really don't know what to do with the "return not num % 2" bit, so as you can see, I just wrote what made sense to me
import random
start = 5
while start:
num = random.randint(1, 99)
if start = False:
break
def even_odd(num):
if num % 2 == 0:
print("{} is even").format(num)
elif num % 2 != 0:
print("{} is odd").format(num)
# If % 2 is 0, the number is even.
# Since 0 is falsey, we have to invert it with not.
return not num % 2
start -= 1
1 Answer
Christopher Shaw
Python Web Development Techdegree Graduate 58,248 PointsUnfortunately, not on track. You should have left even_odd as it was and called the function as you needed it to test a value. So after the original function, start the while loop.
if not even_odd(num):
# matches false
#or
if even_odd(num):
#matches true
Peter Falcone
Courses Plus Student 1,108 PointsPeter Falcone
Courses Plus Student 1,108 Pointsjust gonna keep working at it then, thanks