A weird and puzzling problem!!

Question

I was revisiting some python courses to just brush up on them and I stumbled on this challenge. The challenge is to Write a function named members that takes two arguments, a dictionary and a list of keys. Return a count of how many of the items in the list are also keys in the dictionary.

and this was the I wrote

# You can check for dictionary membership using the
# "key in dict" syntax from lists.

### Example
# my_dict = {'apples': 1, 'bananas': 2, 'coconuts': 3}
# my_list = ['apples', 'coconuts', 'grapes', 'strawberries']
# members(my_dict, my_list) => 2

my_dict = {'apples': 1, 'bananas': 2, 'coconuts': 3}

my_list = ['apples', 'coconuts', 'grapes', 'strawberries']



def members(the_list, the_dict):
  x = 0
  for item in the_dict:
    if item in the_list:
        x = x + 1
    return x

# That function only gives one 

members(my_dict, my_list)

This code for some reason does not yield the desired outcome of 2. It gave one. so I tested the code inside the function and funnily enough it this.

my_dict = {'apples': 1, 'bananas': 2, 'coconuts': 3}
my_list = ['apples', 'coconuts', 'grapes', 'strawberries']
x = 0
for item in my_dict:
    if item in my_list:
        x = x + 1
        print(x)

it gave this

1
2

Can Anyone explain this weird phenomena? Thank In Advance.

Answer 1 · 2015-10-17T15:51:55Z

October 17, 2015 3:51pm

Your return statement is indented too far and is inside the for loop making it return after the first iteration. It will always return "1".

Unindent the return.

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A weird and puzzling problem!!

1 Answer

Chris Freeman

Chris Freeman

zakaria arr

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Chris Freeman

Chris Freeman