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James Wrest
3,480 PointsAdd three more elements to the array: (1) one with a key of "director" and a value of "Irvin Kershner", (2) one with a k
Hi not sure what im doing wrong?
<?php
$movie =array();
$movie["title"] = "The Empire Strikes Back";
$movie["year"] = 1980;
$movie["director"] = "Irvin Kershner";
$movie["imdb_rating"] = 8.8;
$movie["imdb_ranking"] = 11;
?>
<h1><?php echo $movie[title]; ?> (<?php echo $movie["year"])</h1>
<table>
<tr>
<th>Director</th>
<td>Robert Zemeckis</td>
</tr>
<tr>
<th>IMDB Rating</th>
<td>8.5</td>
</tr>
<tr>
<th>IMDB Ranking</th>
<td>53</td>
</tr>
</table>
4 Answers
simhub
26,543 PointsWell! well! I would say, there could be 3 issues..
they may considering a string, not a number ("8.8" not 8.8)
you miss something like ...?>... on the end
<h1><?php echo $movie[title]; ?> (<?php echo $movie["year"] ; ?>)</h1>
And thirdly
<code>........</code>
..........
well! i forgot what it was ;)
anyway this code worked for me:
<?php
$movie=array();
$movie['title']="The Empire Strikes Back";
$movie['year']="1980";
$movie['director']="Irvin Kershner";
$movie['imdb_rating']="8.8";
$movie['imdb_ranking']="11";
?>
<h1><?php echo $movie['title'].' ('.$movie['year'].')';?></h1>
Juliette Tworsey
Front End Web Development Techdegree Graduate 32,425 PointsThis is what worked for me:
movie = array( "title" => "The Empire Strikes Back", "year" => 1980, "director" => "Irvin Kershner", "imdb_rating" => 8.8, "imdb_ranking" => 11, );
Matthew Costigan
18,319 Points<?php
$movie = array ( "title" => "The Empire Strikes Back", "year" => 1980, "director" => "Irvin Kershner", "imdb_rating" => 8.8, "imdb_ranking" => 11,
);
Joy Manuel
6,464 PointsI used [] instead of array ()
<?php $movie = [
"title" => "The Empire Strikes Back", "year" => 1980, "director" => "Irvin Kershner", "imdb_rating" => 8.8, "imdb_ranking" => 11,
]; ?>