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Cliff Jackson
Cliff Jackson
2,886 Points

Bummer: It doesn't look like my favorite flavor is being displayed on the screen. Please check your code and try again.?

What is wrong with this code passes until last part?

output.php
<?php
include "flavor.php";
echo "Hal's favorite flavor of ice cream is . $flavor .";
$flavor = get_flavor();
?>

2 Answers

adam n
adam n
57,278 Points

A couple things. You can't use a variable before it exists. Once you fix that, your result (in preview) will look like:

Hal's favorite flavor of ice cream is . cookie dough .

When it should look like:

Hal's favorite flavor of ice cream is cookie dough.

Let me know if this helps here

Spenser Hale
Spenser Hale
18,329 Points

Hey Cliff

Jennifer already resolved your question here on this second thread you opened. It is best not to open multiple threads. Additional now that your question has been resolved, it would help the community if your close this question by selecting a best answer.

Thanks