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Start your free trialVashisth Bhatt
Python Web Development Techdegree Student 6,786 Pointscan somebody explain why i should use line number 4 to output thing correctly in detailed manner.
i tried line number 4(2nd part) and found output of my programme to be correct but i dodnot get the right explaination
# The dictionary will look something like:
# {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
# 'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Each key will be a Teacher and the value will be a list of courses.
#
# Your code goes below here.
def num_teachers(dict):
count=0
for key in dict.keys():
count+=1
return count
def num_courses(dict):
list1=[]
for value in dict.values():
for course in value:
list1.append(value)
return len(list1)
1 Answer
Chris Freeman
Treehouse Moderator 68,441 PointsYou code works but goes to more effort than needed. Let's look at line by line:
def num_courses(dict):
list1=[] # accumulate results, OK
for value in dict.values(): # for each course_list in teacher courses...
for course in value: # for each course in course_list...
list1.append(value) # append the course_list to results
return len(list1) # count the appended course_lists in the list
So given the input:
{'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
'Kenneth Love': ['Python Basics', 'Python Collections']}
the returned value would be:
len(list1)
len([['jQuery Basics', 'Node.js Basics'], ['jQuery Basics', 'Node.js Basics'], ['Python Basics', 'Python Collections'], ['Python Basics', 'Python Collections']])
4
Since the course_lists are proper lists, you can remove the inner for
loop and use len(value)
. Set a total = 0
before the loops then use total += len(value)
. Now you have a result that can be returned directly.
Post back if you have more questions. Good luck!!