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Bade Unite
7,566 PointsCan someone please tell me, what is the solution of challenge - creating and appending detached dom elements.
Take a moment to read the code in the app.js file. The code should display a modal or pop-over window (built with HTML). In the modal window there should be a place for a message to display and a button to dismiss or close the modal. Check out how the code runs in the preview. There's something wrong. The dismiss button isn't showing in the modal. Can you fix it?
//Create the Modal
var $modal = $("<div id='modal'></div>");
//Create a placeholder for text in the modal
var $placeHolder = $("<p id='placeHolder'></p>");
$modal.append($placeHolder);
//Create a button to dismiss modal and add it to modal
var $dismissButton = $("<button>Dismiss</button>");
//Hide modal when button is pressed
$dismissButton.click(function(){
$modal.hide(300);
});
$("body").append($modal);
//A function to show a modal
function displayModal(message) {
$placeHolder.text(message);
$modal.show();
}
//Show an example modal
displayModal("Hello World!");
<!DOCTYPE html>
<html>
<head>
<link rel="stylesheet" href="css/style.css" type="text/css" media="screen" title="no title" charset="utf-8">
<title>Modal Example</title>
</head>
<body>
<h1>Modal Example Page</h1>
<script src="//code.jquery.com/jquery-1.11.0.min.js" type="text/javascript" charset="utf-8"></script>
<script src="js/app.js" type="text/javascript" charset="utf-8"></script>
</body>
</html>
3 Answers
Roberto Correale
1,539 PointsNot tested locally your code, but the error is that you haven't append the $dismissButton to the modal
var $dismissButton = $("<button>Dismiss</button>");
$modal.append($dismissButton);
Bade Unite
7,566 PointsThank you. It works.
Faisal Rahimi
4,019 Pointsif anyone wnats more clarity on this quiz, do contact me.