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Ruiqi Mao16,675 Points
Cannot pass this PHP task
The 'bummer' message said: You need to specify tables on the JOIN"; https://drive.google.com/open?id=0B1pm90JtbBDMMnFMaV9ORFJWb1k
My answer is:
select * from media as m join media_genres as MG on m.media_id = MG.media_id join genres as g on MG.genre_id = g.genre_id where m.media_id=3;