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Java Java Basics Perfecting the Prototype Looping until the value passes

george petridis
george petridis
1,062 Points
Posted by george petridis
george petridis
1,062 Points

cant do it please help

just cant do it

KnockKnock.java 
/*  So the age old knock knock joke goes like this:

    Person A:  Knock Knock.
    Person B:  Who's there?
    Person A:  Banana
    Person B:  Banana who?
    ...as long as Person A has answered Banana the above repeats endlessly
    ...assuming the person answers Orange we'd see
    Person B:  Orange who?
    ...and then the punchline.
    Person A:  Orange you glad I didn't say Banana again?
    (It's a really bad joke that makes it sound like "Aren't you glad I didn't say Banana again?")

    Let's just assume the only two words passed in from the console from Person B are either banana or orange.
*/

// ====BEGIN PROMPTING CODE====

// Person A asks:
console.printf("Knock Knock.\n");

// Person B asks and Person A's response is stored in the String who:
String who = console.readLine("Who's there?  ");

// Person B responds:
console.printf("%s who?\n", who);

// ==== END PROMPTING CODE ====

3 Answers

Rob Bridges
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.a{fill-rule:evenodd;}techdegree seal-36
Rob Bridges
Full Stack JavaScript Techdegree Graduate 35,467 Points
Rob Bridges
.a{fill-rule:evenodd;}techdegree seal-36
Rob Bridges
Full Stack JavaScript Techdegree Graduate 35,467 Points

Hey there George,

All that is needing to be done is wrap the joke text in a do while loop, the only thing to make sure you do is declare your who variable outside of the loop, so that we can access in step two of this task to print it.

The syntax of a do while loop is

do { // code to run in the loop } while (condition that continues the loop until met)

So, for this one we should wrap out joke in the context of a the loop, like below.

String who;
do {
console.printf("Knock Knock.\n");

// Person B asks and Person A's response is stored in the String who:
 who = console.readLine("Who's there?  ");

// Person B responds:

console.printf("%s who?\n", who);
} while (who.equalsIgnoreCase("banana"));

The next step will ask you to print the who variable to the console, which can be done with something as easy as 

console.printf("%s you glad I didn't say Banana again?", who);

Thanks, hope this helps.

george petridis
george petridis
1,062 Points
george petridis
george petridis
1,062 Points

or i am not so clever hahaha....