Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

iOS Swift Collections and Control Flow Control Flow With Conditional Statements FizzBuzz Challenge

Theo VOGLIMACCI
Theo VOGLIMACCI
8,027 Points
Posted by Theo VOGLIMACCI
Theo VOGLIMACCI
8,027 Points

Can't validate this last exercise FizzBuzz Challenge

Hello, here is my whole response for the FizzBuzz Challenge exercise in swift course. what's wrong?

fizzBuzz.swift 
func fizzBuzz(n: Int) -> String {
  // Enter your code between the two comment markers
 for n in 1...100 {

if (n % 3 == 0) && (n % 5 == 0) {
    return("FizzBuzz")
} else if (n % 3 == 0) {
    return("Fizz")
} else if (n % 5 == 0){
    return("Buzz")
} 

}
  // End code
  return "\(n)"
}

2 Answers

andren
andren
28,558 Points
andren
andren
28,558 Points

There are a number of steps you need to go though for your code to work in this challenge which is listed in the challenge instructions, your code fits all of the criteria except for the last one:

The challenge also does not need you to loop over a range of values (using for or while). I'll take care of that.

You are in fact looping over a range of values, the function that this challenge provides for you is designed to provide the number for you so the loop is not necessary. If you remove the loop from your code like this:

func fizzBuzz(n: Int) -> String {
  // Enter your code between the two comment markers

if (n % 3 == 0) && (n % 5 == 0) {
    return("FizzBuzz")
} else if (n % 3 == 0) {
    return("Fizz")
} else if (n % 5 == 0){
    return("Buzz")
} 
  // End code
  return "\(n)"
}

Then your code will work.