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Python Python Collections (Retired) Lists Redux Manipulating Lists

Posted by MUZ140127 Munyaradzi Muduka
MUZ140127 Munyaradzi Muduka
10,337 Points

challenge 3 of 3,please help am stuck

Now, make the_list contain only the numbers 1 through 20 by using .extend().

lists.py 
the_list = ["a", 2, 3, 1, False, [1, 2, 3]]

# Your code goes below here
a_list = the_list.pop(3)

the_list.insert(0, a_list)

the_list.remove("a")

del the_list[3]


the_list.extend(range(4, 21))

3 Answers

Jamison Imhoff
Jamison Imhoff
12,460 Points
Jamison Imhoff
Jamison Imhoff
12,460 Points

One quick thing noticed is that you only removed "a" and deleted the False boolean. The code you posted above does not erase the List value of [1,2,3]. So your range includes that list in it which may cause errors. If you use the del method be sure to note where the items have moved to since you have del and removed others so the index location (at the start it was 5 for the list) is different after the 2 items were erased. Fix that issue and see if that solves it. if not, let me know and i can give further help.

beven nyamande
beven nyamande
9,575 Points
beven nyamande
beven nyamande
9,575 Points 
the_list = ["a", 2, 3, 1, False, [1, 2, 3]]

# the_list.pop(3)
the_list.insert(idx, the_list.pop(3)) # am inserting what is returned by pop at idx
the_list.remove('a')
the_list.remove(False)
del the_list[len(the_list)-1] # avoid getting indexbound error hence the -1
the_list.extend(range(start_pos,end_pos)) # since you already have the other item
# start_pos the starting position 
# end_pos the ending position
Raj R
PLUS
Raj R
Courses Plus Student 1,095 Points
Raj R
Raj R
Courses Plus Student 1,095 Points

the_list = ["a", 2, 3, 1, False, [1, 2, 3]]

Your code goes below here

the_list.insert(0,the_list.pop(3)) the_list.remove(False) the_list.remove("a") the_list.remove([1,2,3]) del the_list[len(the_list)-1] the_list.extend(range(1,21))

This is not working..whats is wrong??