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PHP Build a Simple PHP Application Creating the Menu and Footer Variables and Conditionals

Devin Scheu
Devin Scheu
66,191 Points

Challenge broken?

Okay so it asks me to check if the flavor variable is the same as randy's favorite flavor. when i preview my code it shows that it works, but the code challenge says its wrong, help?

<?php
$flavor = "cherry";
echo "<p>Your favorite flavor of ice cream is ";
echo $flavor;
echo ".</p>";
echo "<p>Randy's favorite flavor is cookie dough";
if ($flavor == "cookie dough") {
  echo ", also</p>";
}

else {
  echo "</p>";
}
?>

2 Answers

Stone Preston
Stone Preston
42,016 Points

While your code works, it doesnt do what the challenge was asking for. the challenge states: Add a conditional around that final echo command that checks if the flavor variable has a value of "cookie dough." you did not do that. you just need to wrap the original echo statement in an if, dont split the statement like you did. you must follow the directions very carefully

<?php
$flavor = "cherry";
echo "<p>Your favorite flavor of ice cream is ";
echo $flavor;
echo ".</p>";
if ($flavor == "cookie dough") {
echo "<p>Randy's favorite flavor is cookie dough, also!</p>";
 }

?>
Devin Scheu
Devin Scheu
66,191 Points

Thanks Stone, now I understand. I have to wrap the entire text in the if statement. Not just add a part of the text to the end.