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CSS jQuery Basics (2014) Creating a Mobile Drop Down Menu Using each()

Posted by brianbobersky
brianbobersky
9,613 Points

Code Challenge for jQuery Using each

What am I doing wrong? How do I pass the anonymous function?

js/app.js 
//Problem: It look gross in smaller browser widths and small devices
//Solution: To hide the text links and swap them out with a more appropriate navigation

//Create a select and append to #menu
var $select = $("<select></select>");
$("#menu").append($select);

//Cycle over menu links
$("#menu a").each(function(){};
  //Create an option
  //option's value is the href
  //option's text is the text of link
  //append option to select

//Create button 
//Bind click to button
  //Go to select's location
//Modify CSS to hide links on small width and show button and select
  //Also hides select and button on larger width and show's links
//Deal with selected options depending on current page
index.html 
<!DOCTYPE html>
<html>
<head>
<link rel="stylesheet" href="css/style.css" type="text/css" media="screen" title="no title" charset="utf-8">
</head>
<body>
    <div id="menu">
        <ul>
            <li class="selected"><a href="index.html">Home</a></li>
            <li><a href="about.html">About</a></li>
            <li><a href="contact.html">Contact</a></li>
            <li><a href="support.html">Support</a></li>
            <li><a href="faqs.html">FAQs</a></li>
            <li><a href="events.html">Events</a></li>
        </ul>
    </div>
    <h1>Home</h1>
    <p>This is the home page.</p>
    <script src="//code.jquery.com/jquery-1.11.0.min.js" type="text/javascript" charset="utf-8"></script>
    <script src="js/app.js" type="text/javascript" charset="utf-8"></script>
</body>
</html>
caelic
caelic
10,113 Points

if you look at your "each()", you have too many parentheses your code - each(function()(); anonymous function is just "function()", so the code should look like code - each(function());

*to the best of my limited knowledge, sorry if wrong

1 Answer

brianbobersky
brianbobersky
9,613 Points
brianbobersky
brianbobersky
9,613 Points

I found the answer

$("#menu a").each(function () {});