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PHP

Posted by trishagawley
trishagawley
10,483 Points

Code Challenge: stripos

The code is now displaying the right message. Thanks! Let’s change the second variable to a flavor that does start with C to make sure the code still displays the right message: change $var2 to Chocolate.

Oops! It looks like Task 1 is no longer passing.

I understand that 1 should no longer be passing because I changed the $var2, but not sure why it doesn't work for the new $var2.

<?php

    $var1 = "Cookie Dough";
    $var2 = "Vanilla";
    $var2 = "Chocolate";
    $initial = "C";

    if (stripos($var1,$initial) !== 0 && stripos($var2,$initial) !== 0) {

        echo $var1 . " and " . $var2 . " both start with " . $initial . ".";

    } else {

        echo "Either " . $var1 . " or " . $var2 . " doesn't start with " . $initial . "; maybe neither of them do.";

    }

?>

2 Answers

cesare
cesare
15,180 Points
cesare
cesare
15,180 Points

You have to change the value of $var2 instead of replacing it with a new $var2. If you create a new variable to try escaping by the error... I say you that in this period Treehouse has some problem with Code Challenges: for example, if (and other) statements doesn't work.

trishagawley
trishagawley
10,483 Points
trishagawley
trishagawley
10,483 Points 
    $var1 = "Cookie Dough";
    $var2 = "Chocolate";
    $initial = "C";

    if (stripos($var1,$initial) !== 0 && stripos($var2,$initial) !== 0) {

        echo $var1 . " and " . $var2 . " both start with " . $initial . ".";

    } else {

        echo "Either " . $var1 . " or " . $var2 . " doesn't start with " . $initial . "; maybe neither of them do.";

    }

?>

Yea, this doesn't work either...