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PHP Build a Simple PHP Application Creating the Menu and Footer Variables

Brian Platt
Brian Platt
5,009 Points
Posted by Brian Platt
Brian Platt
5,009 Points

Code isn't passing

Hey so for this one my code isn't passing, <?php

$name = "Shirts 4 Mike"; $value = 20;

?>

Any suggestions? Thanks!

2 Answers

Stone Preston
Stone Preston
42,016 Points
Stone Preston
Stone Preston
42,016 Points

You completed task 1 by assigning the name to the variable. Task 2 states: Add another command after this to display the value of the variable on the screen.

so to pass you need to echo your $name variable. you can echo the value of variables out like this:

$variable = "some variable";
echo $variable;
Brian Platt
Brian Platt
5,009 Points
Brian Platt
Brian Platt
5,009 Points

Ok thanks, I just tried to copy the code from the lesson that had a variable for name and price. Thanks, it works now! Brian