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iOS Swift Basics (retired) Control Flow Exercise: FizzBuzz Generator

Andrew Chung
Andrew Chung
5,203 Points
Posted by Andrew Chung
Andrew Chung
5,203 Points

Code not working

for i in 1...20 {
    if (i % 3 == 0) && (i % 5 ==0) {
        println("Fizzbuzz")
    } else if (i % 3 == 0) {
        println("Fizz")
    } else if (i % 5 == 0) {
        println("Buzz")
    } else {
        println(i)
    }
}

From what I can tell my code is identical to the one in the video but xcode is saying that I need a comma after the 5 in the second line.

kjvswift93
kjvswift93
13,515 Points

You need to simply add a space between the == and 0 in your second line.

for i in 1...20 {
    if (i % 3 == 0) && (i % 5 == 0) {
        print("Fizzbuzz")
    } else if (i % 3 == 0) {
        print("Fizz")
    } else if (i % 5 == 0) {
        print("Buzz")
    } else {
        print(i)
    }
}
Andrew Chung
Andrew Chung
5,203 Points
Andrew Chung
Andrew Chung
5,203 Points

Thanks Kyle! I didn't think the spacing mattered but I guess it does in Swift.

1 Answer

Tingting Gu
Tingting Gu
10,760 Points
Tingting Gu
Tingting Gu
10,760 Points

Kyle's answer works. You can also do it in conditions without parentheses.