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JavaScript AJAX Basics (retiring) jQuery and AJAX The Office Status Project Revisited

Posted by J J
J J
15,775 Points

Code not working

$(document.ready(function () {
    var url = "../data/employees.json";
$.getJSON(url, function (response) {
var statusHTML = '<ul class="bulleted">';
$.each(response, function (index, employee) {
if (employee.inoffice === true) {
statusHTML += '<li class = "in">';
} else {
statusHTML += '<li class="out">';
}
  statusHTML += employee.name + '</li>';
});
statusHTML += '</ul>';
  $('#employeeList').html(statusHTML);
});//end json
  });//end ready
Iain Simmons
Iain Simmons
Treehouse Moderator 32,305 Points

Hi J J, I've formatted your code to make it easier to read.

2 Answers

simhub
simhub
26,543 Points
simhub
simhub
26,543 Points

hi J, check also your -$document.ready- function:

    $(document).ready(function () {
...
});

OR more simple 

    $(function () {
...
});

BUT NOT! 

$(document.ready(function () {
...
});
Lukas Smith
Lukas Smith
4,026 Points
Lukas Smith
Lukas Smith
4,026 Points

Check the path : var url = "../data/employees.json"; try var url = "/data/employees.json"; or var url = "data/employees.json";