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Java Java Basics Perfecting the Prototype Looping until the value passes

console.printf

// I have initialized a java.io.Console for you. It is in a variable named console.

Below is the code I entered for the "do; while", test. When I do a check,
I get a response that says: Bummer! Did you use console.printf and to write out the formatted string with the response?

String response; boolean noResponse; do { response = console.readLine("Do you understand do while loops? "); noResponse = (response.equalsIgnoreCase("No")); } while (noResponse);

console.printf("Because you said yes, you passed the test!");

So...what did I do wrong?

Thanks!!

Example.java
// I have initialized a java.io.Console for you. It is in a variable named console.
String response;
boolean noResponse;
do  {
      response = console.readLine("Do you understand do while loops?  ");
      noResponse = (response.equalsIgnoreCase("No"));
    } while (noResponse);

console.printf("Because you said yes, you passed the test!");

1 Answer

Brendon Butler
Brendon Butler
4,254 Points

It looks as if you did not format the output string. It should look something like this:

console.printf("Because you said %s, you passed the test!", response);

Brandon, my man! Thank you!

Diego Camacho
Diego Camacho
644 Points

Thank you for your answer Brendon