Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Python Basics (2015) Logic in Python Membership

Containment

I'm going to create a variable named time. It'll be an integer for the current hour (well, what I want the current hour to be). I need you to make an if condition that sets store_open to True if time is in store_hours. If time isn't in store_hours, set store_open to False. You'll probably have to use if, else, and in to solve this one.

membership.py
store_open = None
store_hours = [9, 10, 11, 12, 13, 14, 15, 16, 17, 18]
if store_open is in store_hours:
  store_open = true
  else:
      if time is not in store_hours:
  store_open = false

1 Answer

Haider Ali
seal-mask
.a{fill-rule:evenodd;}techdegree seal-36
Haider Ali
Python Development Techdegree Graduate 24,728 Points

Hi there. The variable time has already been created for you. you need to check if time is in store_hours using the in keyword. If it is, set store_open to True, if not, set it to False:

store_open = None
store_hours = [9, 10, 11, 12, 13, 14, 15, 16, 17, 18]
if time in store_hours:  #if the current time is in store_hours
  store_open = True      #set store_open to True
else:                    #if it is not in store_hours
  store_open = false     #set store_open to False