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PHP

Posted by Leon Kenedy
Leon Kenedy
Courses Plus Student 9,149 Points

Could you please help with this code challenge?

I need help with a PHP code challenge, I am on number three.

http://teamtreehouse.com/library/build-a-simple-php-application/creating-the-menu-and-footer/variables-and-conditionals

2 Answers

Lucian Melinte
Lucian Melinte
6,853 Points
Lucian Melinte
Lucian Melinte
6,853 Points

Hello Leon,

This is how your code should look like to pass the challenge. However, you could simplify it even further, but I'm sure you will be learning about that in a future assessment.

<?php
$flavor = "vanilla";

echo "<p>Your favorite flavor of ice cream is ";
echo $flavor;
echo ".</p>";

if ($flavor == "cookie dough") {
  echo "<p>Randy's favorite flavor is cookie dough, also!</p>";
} else {
  echo "<p>Seems like you and Randy have different taste.</p>";
}
?>

For stage 4 of the challenge, simply change the variable to this:

<?php
$flavor = "cookie dough";
?>
Leon Kenedy
Leon Kenedy
Courses Plus Student 9,149 Points

I don't know why they would make us put an else statement in if we didn't learn it.

Lucian Melinte
Lucian Melinte
6,853 Points
Lucian Melinte
Lucian Melinte
6,853 Points

I apologize, I haven't taken that course and had no idea that you haven't learned about the else statement yet. It is not necessary to include it in order to pass the challenge. You can simply remove it and the code will still validate.

<?php
$flavor = "vanilla";
echo "<p>Your favorite flavor of ice cream is ";
echo $flavor;
echo ".</p>";
if ($flavor == "cookie dough") {
echo "<p>Randy's favorite flavor is cookie dough, also!</p>";
}
?>
Leon Kenedy
Leon Kenedy
Courses Plus Student 9,149 Points

No, no, you were in no wrong. The code above was completely correct, I still thank you for your help.