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PHP Object-Oriented PHP Basics (Retired) Properties and Methods Mid-Course Challenge

Mathew Coulter
Mathew Coulter
1,998 Points

create a fish object named $bass with the following data name: "Largemouth Bass" flavor: "Excellent" record: "22 pounds

I don't know why it isn't accepting my code. Any help?

fish.php
<?php

class Fish {
  public $common_name;
  public $flavor;
  public $record_weight;

  function __construct($name, $flavor, $record){
    $this->common_name = $name;
    $this->flavor = $flavor;
    $this->record_weight = $record;
  }

$bass = new Fish("Largemouth Bass","Excellent","22 pounds 5 ounces");

}
?>

1 Answer

Mathew Coulter
Mathew Coulter
1,998 Points

I figured it out. I forgot that $bass had to be outside of the class Fish.