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Python Python Collections (2016, retired 2019) Lists Disemvowel

Julian Cardona
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Julian Cardona
Python Web Development Techdegree Student 4,894 Points
Posted by Julian Cardona
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Julian Cardona
Python Web Development Techdegree Student 4,894 Points

disemvowel function

HI! Can someone explain to me why this is wrong?

def disemvowel(word): word = word.lower() word = list(word) for letter in word: if 'a' in word: word.remove('a') if 'e' in word: word.remove('e') if 'i' in word: word.remove('i') if 'o' in word: word.remove('o') if 'u' in word: word.remove('u') word = "".join(word) return word

disemvowel.py 
def disemvowel(word):
    word = word.lower()
    word = list(word)
    for letter in word:
        if 'a' in word:
            word.remove('a')
        if 'e' in word:
            word.remove('e')
        if 'i' in word:
            word.remove('i')
        if 'o' in word:
            word.remove('o')
        if 'u' in word:
            word.remove('u')
    word = "".join(word) 
    return word

1 Answer

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

Any letter that is not removed (not a vowel) should not be altered. But this function coverts the entire word to lower case.

Try: "disemvowel("UPPERCASE")" — the result should be "PPRCS".

Julian Cardona
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.a{fill-rule:evenodd;}techdegree
Julian Cardona
Python Web Development Techdegree Student 4,894 Points
Julian Cardona
.a{fill-rule:evenodd;}techdegree
Julian Cardona
Python Web Development Techdegree Student 4,894 Points

Thanks! Steven! I actually just used a bunch of ifs to look for lower case vowels and upper case vowels. It’s super inefficient but it did the trick

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

If you wanted to make the code more compact, instead of testing individually for each possible vowel, you could test each letter for membership in a string of vowels. :wink: