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Start your free trialchristopher garcia
1,677 PointsDismiss button is not appearing
Its asking me to add a dismiss button to the $modal, I dont know exactly how.
//Create the Modal
var $modal = $("<div id='modal'></div>");
//Create a placeholder for text in the modal
var $placeHolder = $("<p id='placeHolder'></p>");
$modal.append($placeHolder);
//Create a button to dismiss modal and add it to modal
var $dismissButton = $("<button>Dismiss</button>");
//Hide modal when button is pressed
$dismissButton.click(function(){
$modal.hide(300);
});
$("body").append($modal);
//A function to show a modal
function displayModal(message) {
$placeHolder.text(message);
$modal.show();
}
//Show an example modal
displayModal("Hello World!");
<!DOCTYPE html>
<html>
<head>
<link rel="stylesheet" href="css/style.css" type="text/css" media="screen" title="no title" charset="utf-8">
<title>Modal Example</title>
</head>
<body>
<h1>Modal Example Page</h1>
<script src="//code.jquery.com/jquery-1.11.0.min.js" type="text/javascript" charset="utf-8"></script>
<script src="js/app.js" type="text/javascript" charset="utf-8"></script>
</body>
</html>
2 Answers
Leo Van Deuren
8,529 PointsDo you need to append the button to the placeholder?
Matt Milburn
20,786 PointsHi Christopher,
Notice how $placeHolder
was append to $modal
by using $modal.append($placeHolder)
?
Let's borrow that and reuse it for appending $dismissButton
to $placeHolder
in the code below:
//Create a button to dismiss modal and add it to modal
var $dismissButton = $("<button>Dismiss</button>");
$placeHolder.append($dismissButton);