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Python

Posted by Andrew Nally
Andrew Nally
30 Points

Django Page Error 404--url paths

I keep getting a 404 error whenever I click on the Style Info button that is supposed to lead me to the details page on my database manager project using django

these are my views:

def index(request): get_shoes = ShoeClosetModel.ShoeClosetModels.all() context = {'shoeclosetmodels': get_shoes} return render(request, 'ShoeCloset/shoecloset_index.html', context)

def details_shoeclosetmodel(request, pk): pk = int(pk) shoeclosetmodel = get_object_or_404(ShoeClosetModel, pk=pk) context = {'shoeclosetmodel': shoeclosetmodel} return render(request, 'ShoeCloset/shoecloset_details.html', context)

here are my urls:

urlpatterns = [ path('', views.home, name='ShoeCloset'), path('TheShoeCloset', views.index, name='TheShoeCloset'), path('addShoes', views.addShoes, name='addShoes'), path('ShoeCloset/<int:pk>/shoecloset_details', views.details_shoeclosetmodel, name='details'),

]

biplab dasd
.a{fill-rule:evenodd;}techdegree
biplab dasd
Front End Web Development Techdegree Student 191 Points

Yes trying to understand this

def index(request): get_shoes = ShoeClosetModel.ShoeClosetModels.all() context = {'shoeclosetmodels': get_shoes} return render(request, 'ShoeCloset/shoecloset_index.html', context)

def details_shoeclosetmodel(request, pk): pk = int(pk) shoeclosetmodel = get_object_or_404(ShoeClosetModel, pk=pk) context = {'shoeclosetmodel': shoeclosetmodel} return render(request . https://shoespundit.com/best-slip-on-work-boots-for-concrete/ urlpatterns = [ path('', views.home, name='ShoeCloset'), path('TheShoeCloset', views.index, name='TheShoeCloset'), path('addShoes', views.addShoes, name='addShoes'), path('ShoeCloset/<int:pk>/shoecloset_details', views.details_shoeclosetmodel, name='details'),

]