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JavaScript JavaScript Basics (Retired) Creating Reusable Code with Functions Passing an Argument to a Function

Gedalyah (Gary) Frankel
PLUS
Gedalyah (Gary) Frankel
Courses Plus Student 7,234 Points
Posted by Gedalyah (Gary) Frankel
Gedalyah (Gary) Frankel
Courses Plus Student 7,234 Points

Does Somebody have the answer to this Question?

See: https://teamtreehouse.com/library/javascript-basics/creating-reusable-code-with-functions/passing-an-argument-to-a-function

Challenge Task 2 of 2 (I got Task 1, but not Task 2)

After your newly created returnValue function, create a new variable named echo. Set the value of echo to be the results from calling the returnValue function. When you call the returnValue function, make sure to pass in any string you'd like for the parameter.

The function will accept the string you pass to it and return it back (using the return statement). Then your echo variable will be set with what is returned, the results.

script.js 
function returnValue(joe) {
  var echo = 'returnValue('joe')';
  return echo;
}
index.html 
<!DOCTYPE HTML>
<html>
<head>
  <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
  <title>JavaScript Basics</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>

2 Answers

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

The challenge tells you to create the variable after the function.

It looks like you put it inside the function. Put the function back the was it passed task 1. Also, when you assign your variable, be sure to put the quotes only around the argument, not also around the entire call.

Gedalyah (Gary) Frankel
PLUS
Gedalyah (Gary) Frankel
Courses Plus Student 7,234 Points
Gedalyah (Gary) Frankel
Gedalyah (Gary) Frankel
Courses Plus Student 7,234 Points

Thanks Steve. I had a feeling that the variable needed to be outside and put the quotes only around the argument only. In addition I failed because I didn't use straight quotes (i.e., ').