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Python Python Basics (2015) Letter Game App Even or Odd Loop

John Morris
John Morris
4,752 Points

Even or Odd

It is telling me that task one is no longer passing.

even.py
import random

start = 5

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

while start > 0:
    random.randint(1, 99)
    if even_odd(num) == True:
        print("{} is even".format(num))
    else:
        print("{} is odd".format(num))
    start -= 1

1 Answer

Russell Sawyer
seal-mask
.a{fill-rule:evenodd;}techdegree
Russell Sawyer
Front End Web Development Techdegree Student 15,705 Points

You're very close. All you need to do is put the random number into the variable num

while start > 0:
    num = random.randint(1, 99)
    if even_odd(num) == True:
        print("{} is even".format(num))
    else:
        print("{} is odd".format(num))
    start -= 1