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iOS Swift Collections and Control Flow Control Flow With Conditional Statements FizzBuzz Challenge

NAVEED CHOWDHURY
NAVEED CHOWDHURY
1,142 Points
Posted by NAVEED CHOWDHURY
NAVEED CHOWDHURY
1,142 Points

FizzBuzz

why am I getting error

fizzBuzz.swift 
func fizzBuzz(n: Int) -> String {
  // Enter your code between the two comment markers
  for i in 1...100 {
        if (i % 3 == 0) && (i % 5 == 0){
            print("FizzBuzz")
        } else if (i % 3 == 0) {
            print("Fizz")
        } else if (i % 5 == 0) {
            print("Buzz")
        } else {
          print("Nothing")
        }
    }


  // End code
  return "\(n)"
}
Joseph Frazer
Joseph Frazer
5,404 Points
Joseph Frazer
Joseph Frazer
5,404 Points

Lol, maybe post the error?

2 Answers

Jeff McDivitt
Jeff McDivitt
23,970 Points
Jeff McDivitt
Jeff McDivitt
23,970 Points

Hi Naveed - It seems that you missed step 3 of the instructions see below

Step 3: Change all your print statements to return statements. For example: print("FizzBuzz") becomes return "FizzBuzz".

Once you do that the code should pass

func fizzBuzz(n: Int) -> String {
  // Enter your code between the two comment markers

    if (n % 3 == 0) && (n % 5 == 0) {
        return "FizzBuzz"
    } else if (n % 3 == 0) {
        return "Fizz"
    } else if (n % 5 == 0) {
        return "Buzz"
    }
    // End code
  return "\(n)"
}
NAVEED CHOWDHURY
NAVEED CHOWDHURY
1,142 Points
NAVEED CHOWDHURY
NAVEED CHOWDHURY
1,142 Points

I am getting this error message when I type in your code

Bummer! Double check your logic for Buzz values and make sure you're returning the correct string!

Jeff McDivitt
Jeff McDivitt
23,970 Points
Jeff McDivitt
Jeff McDivitt
23,970 Points

That's strange I just copied my exact code into there and it passed

func fizzBuzz(n: Int) -> String {
  // Enter your code between the two comment markers

    if (n % 3 == 0) && (n % 5 == 0) {
        return "FizzBuzz"
    } else if (n % 3 == 0) {
        return "Fizz"
    } else if (n % 5 == 0) {
        return "Buzz"
    }
    // End code
  return "\(n)"
}