fizzbuzz condition

Question

if (number % 3 or number % 5) == 0: I used this statement for fizzbuzz condition, can this also be correct? although it worked.

Answer 1 · 2022-01-09T15:31:30Z

January 9, 2022 3:31pm

It works, but it's "obfuscated" (difficult to read). It relies on the fact that Python considers False to be equal to 0.

A more clear way to test for the same condition would be:

if number % 3 == 0 and number % 5 == 0:

Answer 2 · 2022-01-10T20:39:12Z

January 10, 2022 8:39pm

FizzBuzz can be solved a number of different ways, as you probably know.

The logic for FizzBuzz should be using and as the condition for the test. Something like this:

for number in range(1, 101):
    if number % 3 == 0 and number % 5 == 0:
        print ('FizzBuzz')

Then, to print out the 'Fizz' and 'Buzz' conditions, just use some elif statements to finish the loop.

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